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SVEN [57.7K]
3 years ago
12

Pls answer my module i give 10 pts for this​

Mathematics
1 answer:
jeka943 years ago
5 0

Step-by-step explanation:

what is the problem here you don't understand ?

you understand the words "equality" and "inequality" ?

this is all about the question, if something is equal to something else or not - meaning of they are the same or at least the same size.

an expression without an equal ("=") or unequal sign ("<", ">", ">=", "<=", "<>" - if you don't understand these symbols, please ask, they are simply basic keyboard symbols for the scientific symbols) is not any form of that - no equality, and no inequality.

so,

1. is NOT

2. is NOT because it has an equality symbol

3. is a quadratic inequality (when doing the multiplication of both bracket terms, there will be an x×x=x² part) - it has a ">" (greater) symbol

4. is a quadratic inequality (there is a x² term as highest power of x included) - it has a "<=" (smaller or equal) symbol

5. is a quadratic inequality (there is a x² term as highest power of x included) - it has a ">" (greater) symbol

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Quanto é o resultado e como ae resolve a seguinte operação: 1.205 × 32 Me ajudem preciso para hj.
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Step-by-step explanation:

5 0
3 years ago
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

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50 POINTS IF YOU ANSWER CORRECTLY!
melisa1 [442]

Answer:

<u>Problem 4:</u>  Option C, 32

<u>Problem 5:</u>  You need to have the 2 and the x combine.  Make the table 2x than 16.

<u>Problem 6:</u>  x = 17

<u>Problem 7:</u>  She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

Step-by-step explanation:

<u>Problem 4</u>

2 + x + 16 = 50

x + 18 - 18 = 50 - 18

x = 32

Answer:  Option C, 32

<u>Problem 5</u>

You need to have the 2 and the x combine.  Make the table 2x than 16.

Answer:  You need to have the 2 and the x combine.  Make the table 2x than 16.

<u>Problem 6</u>

2x + 16 - 16 = 50 - 16

2x / 2 = 34 / 2

x = 17

Answer:  x = 17

<u>Problem 7</u>

She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

Answer: She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

4 0
3 years ago
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In the radian system of angular measurement, what is the measure of one revolution?
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Answer:

option

A. 2x

Step-by-step explanation:

Mark brainliest

6 0
2 years ago
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