Answer:
The height of the tree is H = 77.06 m
Step-by-step explanation:
From Δ ABC
AB = height of the tree
h = 0.9623 x ------- (1)
From Δ ABD
h = 0.77 (x + 20) ----- (2)
Equating Equation 1 & 2 we get
0.9623 x = 0.77 (x + 20)
0.9623 x = 0.77 x + 15.4
x (0.1923) = 15.4
x = 80.08 m
Thus the height of the tree is given by
H = 0.9623 x
H = 0.9623 × 80.08
H = 77.06 m
Therefore the height of the tree is H = 77.06 m
Slant height of tetrahedron is=6.53cm
Volume of the tetrahedron is=60.35
Given:
Length of each edge a=8cm
To find:
Slant height and volume of the tetrahedron
<u>Step by Step Explanation: </u>
Solution;
Formula for calculating slant height is given as
Slant height=
Where a= length of each edge
Slant height=
=
==6.53cm
Similarly formula used for calculating volume is given as
Volume of the tetrahedron=
Substitute the value of a in above equation we get
Volume=
=
=
Volume==60.35
Result:
Thus the slant height and volume of tetrahedron are 6.53cm and 60.35