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3 years ago

Solve for x. 39 = 3х

Mathematics

1 answer:

devlian [24]3 years ago

5 0

Hopes this helps:

Answer: x = 13

Please mark as brainlist if it’s right.

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I don't understand this class and my teacher is stupid and won't go over it again to help me better understand

allochka39001 [22]

Answer:

Well i believe the answer is obtuse

Step-by-step explanation:

4 0

3 years ago

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If j = k, then j + 9 = k + 9 represents which algebraic property

sleet_krkn [62]

Answer:

c) The given expression represents Addition Property of Equality.

Step-by-step explanation:

Here, the given expression is j = k

Now by ADDITION PROPERTY OF EQUALITY:

The property that states that if you add the same number to both sides of an equation, the sides remain equal.

So, if A = B ⇒ A + x = B + x

Now, here given that j = k

If we add the same number 9 on both the sides, the equation remains undisturbed.

⇒ j + 9 = k + 9

Hence, the above expression represents Addition Property of Equality.

8 0

4 years ago

Hi! how many times does 9 go into 67???? plz help me

Nina [5.8K]

Answer:

it goes into 67 7 times

Step-by-step explanation:

8 0

4 years ago

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The x- intercepts of a parabola are (0,-6) and (0,4). The parabola crosses the y- axis at -120. Lucas said that an equation for

astraxan [27]

Given:

The x- intercepts of a parabola are (0,-6) and (0,4).

The parabola crosses the y- axis at -120.

Lucas said that an equation for the parabola is $y=5x^2+10x-120$ and that the coordinates of the vertex are (-1, -125).

To find:

Whether Lucas is correct or not.

Solution:

The x- intercepts of a parabola are (0,-6) and (0,4). It means (x+6) and (x-4) are the factors of the equation of the parabola.

$y=a(x+6)(x-4)$ ...(i)

The parabola crosses the y- axis at -120. It means the equation of the parabola must be true for (0,-120).

$-120=a(0+6)(0-4)$

$-120=a(6)(-4)$

$-120=-24a$

Divide both sides by -24.

$\dfrac{-120}{-24}=a$

$5=a$

Substituting $a=5$ in (i), we get

$y=5(x+6)(x-4)$

$y=5(x^2+6x-4x-24)$

$y=5(x^2+2x-24)$

$y=5x^2+10x-120$

So, the equation of the parabola is $y=5x^2+10x-120$ .

The vertex of a parabola $f(x)=ax^2+bx+c$ is:

$Vertex=\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)$

In the equation of the parabola, $a=5,b=10,c=-120$ .

$-\dfrac{b}{2a}=-\dfrac{10}{2(5)}$

$-\dfrac{b}{2a}=-\dfrac{10}{10}$

$-\dfrac{b}{2a}=-1$

Putting $x=-1$ in the equation of the parabola, we get

$y=5(-1)^2+10(-1)-120$

$y=5-10-120$

$y=-125$

So, the vertex of the parabola is at point (-1,-125).

Therefore, Lucas is correct.

5 0

3 years ago

235000000000 in scientific notation ?

yuradex [85]

235,000,000,000 is the answer to your question.

5 0

3 years ago

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