All categories

3 years ago

Im having a hard time plss help

Mathematics

2 answers:

vivado [14]3 years ago

6 0

Answer:

112.5÷15=7.5

Step-by-step explanation:

Well we know that the larger number has to go first, so that gets rid of 2, and the answer as 75 is way to high to be dividing by 15!

I hope this helps, and have a great day!

Dahasolnce [82]3 years ago

3 0

The 2nd one is right
112.5 divided by 15 is 7.5

You might be interested in

X + 6 = x – 1<br><br> Find x.

Lady bird [3.3K]

I think it’s no solution

6 0

3 years ago

Read 2 more answers

How long does it take for a bee to fly 12 miles going 15 mph?

sladkih [1.3K]

Two hours ! i think i'm not good at many

4 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

I need h3lpppppppppppppppppppppppppppppppppp

Amanda [17]

The answer is E because during 5:00-9:00 the temperature didn’t change

7 0

3 years ago

The answer is A I just need help working it out

nordsb [41]

STU + STR = 180
8x + STR = 180 [ STU = 8x ]
STR = 180 - 8x

STR = SRT [ RS ≈ ST ]

Now, In ΔSRT,
we have, RST = 7x - 54, STR = SRT = 180-8x
Their sum is 180, as it constitutes a triangle.

7x-54 + 2(180-8x) = 180
7x - 54 + 360 - 16x = 180
306 - 9x = 180
9x = 306 - 180
9x = 306 - 180
x = 126/9
x = 14

So, option A is your answer.

Hope this helps!

5 0

3 years ago

Read 2 more answers