For anyone seeing this that is in k12 the answer is definitely 6. Don't listen to the guy saying it's 9. Have a nice day :)
Answer:
4 sec
Step-by-step explanation:
let y = 0 which is the height when the rocket hits the ground
-3t^2 + 6t + 24 = 0
-3(t^2 - 2t - 8) = 0
-3(t - 4)(t + 2) = 0
t = 4 or t = -2
time cannot be negative, so t = 4 sec
Answer:
\frac{n}{9}-6
Step-by-step explanation:
Answer:
linear
Step-by-step explanation:
Where is the picture for this problem???
Answer:
73°
Step-by-step explanation:
Given: BD=BE
∠DBE= 50°
∠EAC= 42°
DE//AC and AE=CD
Attach is the new drawn diagram with M point.
∵ we know BD=BE, ∴ ∠BDE=∠BED= x ( taking x as unknown angle)
Remember, sum of triangle= 180°
Now, ∠BDE+∠BDE+∠DBE= 180°
⇒ 
⇒ 
Subtracting both side by 50, then dividing both side by 2
∴
°
We know, ∠MAC= ∠MCA= 42° (∵AM=MC)
Next, ∠EDC=DCA= 42° ( ∵ Alternate interior angle as we know DE//AC )
Now, we have ∠EDC= 42°, ∠BDE= 65°
∴
° (∵sum of straight line= 180°)
⇒
°
⇒
°
Subtracting both side by 107
∴∠ADC=
°
∴∠ADC= 73°