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Lelu [443]
4 years ago
6

Find the zeros of the function.

2B%20100" id="TexFormula1" title=" h(x) = {x}^{2} + 29x + 100" alt=" h(x) = {x}^{2} + 29x + 100" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Naddika [18.5K]4 years ago
3 0

0=x^2+29x+100

x= (-b +sqrt(b^2-4ac))/2a     x=(-b -sqrt(b^2-4ac))/2a

x=(-(29)+sqrt((29)^2-4(1)(100)))/2(1)      x=(-(29)+sqrt((29)^2+4(1)(100)))/2(1)

x=(-29+sqrt441)/2       x=(-29-sqrt441)/2

x=(-29+21)/2      x=(-29-21)/2

x=-8/2    x=-50/2

x= -4    x= -25

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To find the maximum value of the function f(x) = -3(x - 10)(x - 4), the easiest way is to find the vertex using the formula: x = -b/2a.

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f(x) = -3(x - 10)(x - 4)

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Answer:

-3

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