Question

Find the zeros of the function.2B%20100" id="TexFormula1" title=" h(x) = {x}^{2} + 29x + 100" alt=" h(x) = {x}^{2} + 29x + 100" align="absmiddle" class="latex-formula">

Answer 1

0=x^2+29x+100

x= (-b +sqrt(b^2-4ac))/2a     x=(-b -sqrt(b^2-4ac))/2a

x=(-(29)+sqrt((29)^2-4(1)(100)))/2(1)      x=(-(29)+sqrt((29)^2+4(1)(100)))/2(1)

x=(-29+sqrt441)/2       x=(-29-sqrt441)/2

x=(-29+21)/2      x=(-29-21)/2

x=-8/2    x=-50/2

x= -4    x= -25