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skad [1K]
3 years ago
8

Gabriel will randomly choose one can of soup then

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

Is the question fully attached?

Step-by-step explanation:

I dont see any numbers do you have a picture of the question?

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Come hither big brains
katrin2010 [14]

Answer:

The answer is c

Step-by-step explanation:

7 0
3 years ago
Complete each ordered pair so that it is a solution of the given linear equation
Anastasy [175]

Answer:

(3, -2) and (9, 0)

Step-by-step explanation:

x-3(-2)=9

x+6= 9

x=3

9-3y=9

-3y=0

y=0

3 0
3 years ago
If Half the number is 40 less than 56. Find the number
pogonyaev

Answer:

32

Step-by-step explanation:  

half the number is 56 - 40 which is 16 and it says half the nuber is 16 so 16 x 2 is 32

5 0
3 years ago
Read 2 more answers
Kareem and Marco went to the mall. Kareem spent $8 less than Marco spent at the mall. Kareem spent more than $15. Write an inequ
mestny [16]
Marco spent more than $23. M > 23

We know the Kareem spent 8 less than Marco and that Kareem spent more than 15. If we add 8 onto the 15, we know that Marco has to be more than 23.

To graph this, draw an open circle at 23 and have an arrow going to the right.
4 0
4 years ago
In a chess club the probability that Shaun will beat Mike is 3/8 .
romanna [79]

Answer:

\frac{10}{56} = 0.1786 probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So 1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8} probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So 1 - \frac{5}{7} = \frac{2}{7} probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786

\frac{10}{56} = 0.1786 probability that Shaun loses both games

3 0
3 years ago
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