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storchak [24]
4 years ago
6

do you agree that the equation (x-4)²=9 can be solved both by factoring and extracting square roots? ​

Mathematics
1 answer:
zvonat [6]4 years ago
7 0

Given parameters:

  Equation:

          (x-4)²=9

Problem, solve the equation by factoring and extracting the root

<u>Solution:</u>

    Given equation:

                  (x-4)²=9

         subtract 9 from both sides to equate to zero;

                (x-4)² - 9 = 0

                (x -4)² - 3² = 0

  Now, this is similar to the concept of difference of two squares;

          x² - y² = <em>(x + y)(x-y)</em>

                     

Here x  = x-4 and y = -3

  So input and solve;

              (x - 4 -3)(x - 4 -(-3)) = 0

              (x - 7)(x - 4+3) = 0

              (x -7)(x -1) = 0

S0,

             x - 7 = 0 or x-1 = 0

             x = 7 or 1

If we extract the square roots;

          (x-4)² = 9

         √(x-4)² = √9

              x - 4 = 3

              x  = 4 + 3 = 7; this is not the only solution to the problem

So we cannot solve it by extracting the square root.

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ANSWER

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EXPLANATION

The equation of a parabola in factored form is

y = a(x + m)(x + n)

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From the question, the zeros of the parabola are 6 and −5.

This implies that,

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We plug in these zeros to get:

y= a(x +6)(x  - 5)

If (-1, 3) is a point on the graph of this parabola,then it must satisfy its equation.

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3= a( - 1 +6)( - 1  - 5)

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