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valentinak56 [21]
2 years ago
9

In mathematics given that x=L2-L1/L1(O2-O1).

Mathematics
1 answer:
Assoli18 [71]2 years ago
4 0

Answer:

1. L1 = \frac{L2}{X(O2 -O1)}

2. O2 = \frac{L2 - L1(1 + XO1)}{XL1}

Step-by-step explanation:

Given: x = \frac{L2 - L1}{L1(O2 -O1)}

1. To make L1 the subject of formula;

x = \frac{L2 - L1}{L1(O2 -O1)}

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

collect like terms,

L2 = xL1(O2 - O1) + L1

factorize the right hand side;

L2 = L1[x(O2 - O1)]

L1 = \frac{L2}{X(O2 -O1)}

2. To make O2 the subject of formula;

x = \frac{L2 - L1}{L1(O2 -O1)}

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

open the bracket to have;

L2 - L1 = xL1O2 - xL1O1

⇒ xL1O2 = L2 - L1 + xL1O1

O2 = \frac{L2-L1 + XL1O1}{XL1}

     = \frac{L2 - L1(1 + XO1)}{XL1}

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\huge{\underline{\boxed{\tt{Answer:}}}}

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

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