3 years ago

Solve the equation: (x^4 - x + y)dx - xdy=0

1 answer:

5 0

Keeping in mind that "dx" is the delta x, or differential over the x-axis, whilst "dy" is the delta y or differential over the y-axis,

$\bf (x^4-x+y)dx-xdy=0\implies \stackrel{\textit{distributing dx}}{x^4dx-xdx+ydx}-xdy=0
\\\\\\
ydx=xdy-x^4dx+xdx\implies y=\cfrac{xdy-x^4dx+xdx}{dx}
\\\\\\
y=\stackrel{\textit{distributing the denominator}}{x\cfrac{dy}{dx}-x^4+x}$

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7 0

3 years ago

Find the vertex form of the function then find the following a) intercepts b) vertex c) maximum or minimum d) range

Ganezh [65]

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y-intercept; (0, -40)
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3 years ago

How do I find a7? Currently getting a even #

Katarina [22]

we know that a₁ = 1, and aₙ = aₙ₋₁ + 2, is another way of saying, we add 2 to get the next term, namely, 2 is the common difference.

$\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\[-0.5em]
\hrulefill\\
a_1=1\\
d=2\\
n=7
\end{cases}
\\\\\\
a_7=1+(7-1)2\implies a_7=1+12\implies a_7=13$