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AlekseyPX
3 years ago
15

Paula's time swimming in the Ironman Triathlon was 1 hour 25 minutes. Her time biking was 5 hours longer than her swimming time.

She ran for 4 hours 50 minutes. How long did it take her to complete all three parts of the race? Use the model to help you organize your thinking.
Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer: 12 hrs 40 mins

Step-by-step explanation:

The swimming time was 1 hour 25 minutes.

Her biking time was 5 hours longer than the swimming time so it was:

= 1 hr 25 mins + 5 hours

= 6 hours 25 mins

Her running time was 4 hrs 50 mins.

Add them all up to find the amount of time ran. First add up the minutes:

= 25 + 25 +50

= 1 hr 40 minutes

Hours = 1 + 6 + 4

= 11 hours

Total:

= 11 + 1 hr 40

= 12 hrs 40 mins

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HURRRY! ILL GIVE BRAINLEST Mrs. Jordan surveyed all of her students to find out which testing format they prefer. Of the 120 stu
taurus [48]

Answer:

50%

Step-by-step explanation:

30+10=40

40+20=60

120-60=60

60 is 50% of 120

3 0
3 years ago
Read 2 more answers
. If a car can travel 38 miles on 2.4 gallons of gas, how many miles could the car travel on 6 gallons of gas?
lilavasa [31]

Answer:

About 95 miles

Step-by-step explanation:

Let's set up a proportion using the following set up:

miles / gallons = miles / gallons

We know the car can travel 38 miles on 2.4 gallons of gas.

38 miles / 2.4 gallons = miles/ gallons

We don't know how far the car can travel on 6 gallons. Therefore, we can say the car travels x miles on 6 gallons of gas.

38 miles / 2.4 gallons = x miles /6 gallons

38/2.4=x/6

We want to find x (miles for 6 gallons). Therefore, we must isolate x.

x is being divided by 6. The inverse of division is multiplication. Multiply both sides by 6.

6*(38/2.4)=(x/6)*6

6*(38/2.4)=x

6*15.8333333=x

94.9999998=x

Let's round to the nearest whole number. The 9 in the tenth place tells us to round up.

95 ≈x

x ≈95 miles

The car can travel about 95 miles on 6 gallons of gas.

6 0
3 years ago
Can someone help me solve this? I have no idea what property to use!
maks197457 [2]
First you distribute-3 to -4y and 3 leaving you with 12y+(-9)+7y. Now combine like terms, so your answer is 19y-9
3 0
4 years ago
Read 2 more answers
In isosceles triangle ABC, AB=AC.If B=55, calculate A​
den301095 [7]

Answer: ∠A = 70°

because ABC is an  isosceles triangle and AB =  AC

=> ∠B = ∠C = 55°

=> ∠A = 180-(∠B + ∠C) = 180° - 55°.2 = 70°

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
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