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tigry1 [53]
3 years ago
13

. If a car can travel 38 miles on 2.4 gallons of gas, how many miles could the car travel on 6 gallons of gas?

Mathematics
1 answer:
lilavasa [31]3 years ago
6 0

Answer:

About 95 miles

Step-by-step explanation:

Let's set up a proportion using the following set up:

miles / gallons = miles / gallons

We know the car can travel 38 miles on 2.4 gallons of gas.

38 miles / 2.4 gallons = miles/ gallons

We don't know how far the car can travel on 6 gallons. Therefore, we can say the car travels x miles on 6 gallons of gas.

38 miles / 2.4 gallons = x miles /6 gallons

38/2.4=x/6

We want to find x (miles for 6 gallons). Therefore, we must isolate x.

x is being divided by 6. The inverse of division is multiplication. Multiply both sides by 6.

6*(38/2.4)=(x/6)*6

6*(38/2.4)=x

6*15.8333333=x

94.9999998=x

Let's round to the nearest whole number. The 9 in the tenth place tells us to round up.

95 ≈x

x ≈95 miles

The car can travel about 95 miles on 6 gallons of gas.

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Sveta_85 [38]

Josh's monthly fuel expenses are $1,050.

<h3><u>Prices</u></h3>

Given that Josh is looking to get a new car because he decided he was spending too much on gas, and over the past year he found that he drove 7,700 miles, and at current gas prices of $4.5 he was getting about 27 miles per gallon, To determine, if he bought a vehicle that realizes 33 miles per gallon, what might be a reasonable estimate of monthly gas costs, the following calculation must be made:

  • 27 = 100
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Therefore, Josh's monthly fuel expenses are $1,050.

Learn more about prices in brainly.com/question/18117910

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2 years ago
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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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3 years ago
The fourth term of an Arithmetic Sequence is equal to 3 times the first term, and the seventh term exceeds twice the third term
11Alexandr11 [23.1K]

Answer:

The first term is 3. The common difference is 2.

Step-by-step explanation:

The first term is x.

The common difference is d.

The second term is x + d.

3rd term: x + 2d

4th term: x + 3d

7th term: x + 6d

"The fourth term of an Arithmetic Sequence is equal to 3 times the first term"

x + 3d = 3 * x       Eq. 1

"the seventh term exceeds twice the third term by 1"

x + 6d = 2(x + 2d) + 1       Eq. 2

Simplify Eq. 1:

2x = 3d

Simplify Eq. 2:

x + 6d = 2x + 4d + 1

x = 2d - 1

Multiply both sides of the last equation by 2.

2x = 4d - 2

2x = 3d   (simplified Eq. 1)

Since 2x = 2x, then the right sides are equal.

3d = 4d - 2

d = 2

2x = 3d

2x = 3(2)

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Answer: The first term is 3. The common difference is 2.

8 0
3 years ago
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