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2 years ago

. If a car can travel 38 miles on 2.4 gallons of gas, how many miles could the car travel on 6 gallons of gas?

Mathematics

1 answer:

lilavasa [31]2 years ago

6 0

Answer:

About 95 miles

Step-by-step explanation:

Let's set up a proportion using the following set up:

miles / gallons = miles / gallons

We know the car can travel 38 miles on 2.4 gallons of gas.

38 miles / 2.4 gallons = miles/ gallons

We don't know how far the car can travel on 6 gallons. Therefore, we can say the car travels x miles on 6 gallons of gas.

38 miles / 2.4 gallons = x miles /6 gallons

38/2.4=x/6

We want to find x (miles for 6 gallons). Therefore, we must isolate x.

x is being divided by 6. The inverse of division is multiplication. Multiply both sides by 6.

6*(38/2.4)=(x/6)*6

6*(38/2.4)=x

6*15.8333333=x

94.9999998=x

Let's round to the nearest whole number. The 9 in the tenth place tells us to round up.

95 ≈x

x ≈95 miles

The car can travel about 95 miles on 6 gallons of gas.

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The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea

Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that $P(A \cap B) = 0.03$

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that $P(A) = 0.03 + 0.7 = 0.73$

What is the probability of the following event: He has lung disease given that he does not smoke?

$P(B|A) = \frac{0.03}{0.73} = 0.0411$

4.11% probability that he has lung disease given that he does not smoke

5 0

2 years ago

If letters of the word COMPUTER are randomly arranged in a row, what is the probability that the letters CO remain next to each

Mariana [72]

The probability that the letters CO remain next to each other (in order) as a unit is $\frac{1}{8}$ .

<h3>What is probability?</h3>

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty. It is more likely that an event will occur if its probability is higher.

When the letters are arranged randomly in a row, the total number of arrangements is 40,320 , and the number of arrangements with the letters CO next to each other (in order) as a unit is 5,040.

Therefore, possible outcomes = 5040 and

Total outcomes = 40320

Probability = $\frac{Possible outcomes}{Total outcomes}$