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Mademuasel [1]
3 years ago
13

Why must all chemical reactions be balanced?

Biology
1 answer:
makvit [3.9K]3 years ago
6 0

so that it follows the law of conservation of mass.

have a goed day

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Take your time to review the pic provided Then answer,Is my response accurate? The subject is Kudzu and the questions are at the
Ahat [919]

Over all, it is a pretty good answer and very complete. I wouldn't say Kudzu "climbs", I suggest just to say it grows up on other plants and trees affecting them negatively by suffocating them.

Maybe you could explain a little bit more about the characteristics of the plant.

It is excellent how you say it is an agressive and competitor but I wouldn't compare it with a predator, maybe more with a parasite.

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2 years ago
Suppose a species of bird called the red‑crested warbler has a plumage length that is controlled by a single gene. The P????mPlm
andreev551 [17]

Answer:

Check the explanation

Explanation:

North American:

112 birds total => 224 alleles

112 - 55 birds = 57 short plume birds.

q^2= (2*57) / 224 = 0.5089

Freq(short plume allele) = q = 0.7134

Freq(long plume allele) = p = 1 - q = 0.2866

From this North American population we get

0.2866 * 224 = 64 long plume alleles

0.7134 * 224 = 160 short plume alleles

South American:

452 birds total => 904 alleles

452 - 75 birds = 377 short plume birds.

q^2 = (2*377) / 904 = 0.8341

Freq(short plume allele) = q = 0.9133

Freq(long plume allele) = p = 1 - q = 0.0867

From this South American population we get

0.0867 * 904 = 78 long plume alleles

0.9133 * 904 = 826 short plume alleles

Blended population has

64 + 78 = 142 long plume alleles

160 + 826 = 986 short plume alleles

142 + 986 = 1128 total alleles

p = 142/1128 = 0.1259

q = 986/1128 = 0.8741

All right. The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.1259^2 + 2*0.1259*0.8741) = 236 birds

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Answer:

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