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3 years ago

I need help with this math please

Mathematics

2 answers:

Readme [11.4K]3 years ago

6 0

Answer:

question 1: it is between 8 and 9. question 2: option B.

Step-by-step explanation:

1. since the closest value that IS a squarable number is 64, the square root of 64 is 8. because 66 is greater than 64, we can estimate that the square root of 66 is between 8 and 9.

2. to solve this, we can take the square root of the numbers to begin.

the square root of 25 is 5 (because 5x5=25)

the square root of 16 is 4

20 is actually not squarable, so we can estimate that it is a little greater 4.

the answer would be √16, √20, 4.85, √25

it would be option b.

hope this helps!! :))

lara [203]3 years ago

3 0

Question one is last option between 8 and 9

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Find the value of x in the equation x⁄ 4 + x⁄14 + x⁄17 = 71

Morgarella [4.7K]

Hello from MrBillDoesMath!

Answer:

33769/181

Discussion:

Each term contains "x" so factoring it out gives

x( 1/4 + 1/14 + 1/17) = 71 (*)

Use common factor (17*14*4 = 952) as the denominator to combine terms:

1/4 = (17*14)/ 952 = 238/952

1/14 = (17*4)/952 = 68/952

1/17 = (14*4)/952 = 56/952

so 1/4 + 1/14 + 1/17 = (238 + 68 + 56)/ 952 = 362/952 = 181/476

Substituting in (*) gives

x ( 181/476) = 71 => multiply both sides by 476/181

x = (71 * 476)/181 => 71* 476 =33769

x = 33769/181

Thank you,

MrB

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