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Kipish [7]
3 years ago
13

ABCD is a rhombus. Given only the choices below, which properties would you use to prove AEB ≅ DEC by SAS?

Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

The diagonals bisect each other.

Step-by-step explanation:

Given

Rhombus ABCD

Required

Which property proves AEB ≅ DEC by SAS

From the question, we understand that the property is to be proved by SAS; SAS implies that Side-Angle-Side

We can assume that point E is where the diagonals meet.

So, we have:

Equal sides: AE = DE and BE = CD

Equal angle: <E = <E

The above implies that the diagonals bisect one another.

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Whats the answer to that question?
gavmur [86]

Answer:

-0.9090... can be written as \frac{10}{11}.

Explanation:

Any <em>repeating </em>decimal can be written as a fraction by dividing the section of the pattern to be repeated <em>by </em>9's.

We can start by listing out

0.909090... = 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...

Now. we let this series be equal to x, that is

x = 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...

Now, we'll multiply both sides by 100 .

100x = 90 + 0 + 9/10 + 0/100 + 9/1000 + 0/10000 + ...

Then, subtract the 1st equation from the second like so:

100x = 90 + 0 + 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...

-x = - 9/10 - 0/100 - 9/1000 - 0/10000 - 9/100000 - 0/1000000 - ...

And we end up with this:

99x=90

Finally, we divide both sides by 99 in order to isolate x and get the fraction we're looking for.

x=\frac{90}{99}

Which can be reduced and simplified to

x=\frac{10}{11}

Hope this helps!

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What is the measure of
snow_tiger [21]
3x=90 2x=50
And the last one is 40
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