Look at the image below
2 answers:
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So attached is a picture of the triangle you are talking about and listed under are the choices:
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.
Answer:
Slope of required line if both lines are parallel: y=4x-20
Slope of required line if both lines are perpendicular: y=-1/4x+14
Step-by-step explanation:
We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)
<u><em>Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.</em></u>
If Both lines are parallel the equation of new line will be:
We need to find slope and y-intercept to write equation of new line.
When lines are parallel there slopes are same
So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)
Slope of new line is: m=4
Now finding y-intercept
Using slope m=4 and point (8,12) we can find y-intercept
y-intercept of new line is: b=-20
Equation of required line having slope m=4 and y-intercept b=-20 is
If Both lines are perpendicular the equation of new line will be:
We need to find slope and y-intercept to write equation of new line.
When lines are perpendicular there slopes are opposite of each other
So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)
Slope of new line is: m=-1/4
Now finding y-intercept
Using slope m=-1/4 and point (8,12) we can find y-intercept
y-intercept of new line is: b=14
Equation of required line having slope m=-1/4 and y-intercept b=14 is