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2 years ago

Look at the image below

Mathematics

2 answers:

Nutka1998 [239]2 years ago

7 0

The answer should be 3619.1km³

xeze [42]2 years ago

3 0

Answer:

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PLS HURRY WILL GIVE BRAINLIEST

marta [7]

Answer:

C. y= 6x-5

Step-by-step explanation:

Given Information :

Slope (m) = 6

y-intercept (b) = -5

Equation of a line :

y=mx+b

Where :

m = slope

b = y-intercept

So , with the given the information , the equation is :

$y = 6x - 5$

7 0

3 years ago

-5 + 8 • -7 <br> help lols

iris [78.8K]

Answer:

Step-by-step explanation:

-5 + (8 x -7)

using PEMDAS, (8 x -7) = -56

so -5 + -56 = -61

5 0

2 years ago

How to solve this equation

mariarad [96]

$\bf \sqrt{5x+19}-4=3x-15
\\\\
\sqrt{5x+19}=3x-15+4\\\\ \sqrt{5x+19}=3x-11\leftarrow \textit{square both sides}
\\\\
(\sqrt{5x+19})^2=(3x-11)^2
\\\\
5x+19=(3x-11)^2\qquad 
\begin{cases}
(3x-11)^2\to (3x-11)(3x-11)\\
 --------------\\
\textit{or use FOIL to expand it}
\end{cases}$

then solve for "x"

7 0

2 years ago

What is 10 1/12 as a decimal

cricket20 [7]

Answer:

10.083

since 1/12 is .0833333333 and so on, it’s shortened

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

3 years ago