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kirza4 [7]
3 years ago
6

What is sampling?

Computers and Technology
1 answer:
Mama L [17]3 years ago
3 0
The answer is either B) or D) because I remember learning this and the keyword I remember is analogue

Hope this helps —- XoXo
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1.152 GB if it will be at 128 kbps quality

Explanation:

So, let's say you choose your mp3 be 128 kbps (kilobits per second).

One byte is 8 bits. So 128 kbps = 16 kilobytes per second.

There is 60*60 seconds in one hour. So 16*60*60 = 57.6 megabytes per hour

Multiply by 20 hours to get your answer: 57.6*20 = 1152 MB = 1.152 GB.

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Because due to pandemic all the offices and employment sector are closed physically and to make their work smoothly people are preferring virtual platforms with the concept of work from home .

I hope it is helpful and mark me as brainlest and follow me plllzzz♥️♥️

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How to download ram<br> my computer is very slow and I need more ram
AURORKA [14]

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It is not possible to download RAM onto your computer.

Explanation:

RAM (Random-Access Memory) are physical objects installed onto your computer in the form of some sort of chip. Please do not attempt to download RAM from the internet, you may end up with malicious software on your computer. The only way to get more RAM is by installing more onto your computer or by looking at guides that can explain how to free up some RAM that may already be in use by an application.

8 0
3 years ago
Read 2 more answers
2. Write a program that calls creates an ArrayList of integer and calls the method minToFront described below. Print out the lis
Novosadov [1.4K]

Answer:

import java.util.ArrayList;

public class MinToFront {

   public static void minToFront(ArrayList < Integer > list){

       int miniIndex = 0;

       for(int j=1; j<list.size(); j++){

          if(list.get(miniIndex) > list.get(j))

               miniIndex = j;

      }

      // moving min to front

       int min = list.get(miniIndex);

       list.remove(miniIndex);

       list.add(0, min);

  }

  public static void main(String[] args) {

       ArrayList<Integer> list = new ArrayList<>();

      list.add(4);   //value store in list

      list.add(7);   //value store in list

      list.add(9);  //value store in list

      list.add(2);  //value store in list

      list.add(7);  //value store in list

      list.add(7);  //value store in list

      list.add(5);  //value store in list

       

      list.add(3);  //value store in list

       

      list.add(5);  //value store in list

       

      list.add(1);  //value store in list

       

      list.add(7);  //value store in list

       

      list.add(8);  //value store in list

       

      list.add(6);  //value store in list

       

      list.add(7);  //value store in list

       

      System.out.println(list);

      minToFront(list);

      System.out.println(list);

  }

}

Output:

[1, 4, 7, 9, 2, 7, 7, 5, 3, 5, 7, 8, 6, 7]

Explanation:

Firstly,we define a method minToFront(), than set an integer variable "miniIndex" to 0, than set a for loop and apply the following condition and inside the loop we apply the if condition, set an integer variable "min" in which we store the value and than we set the following list [4, 7, 9, 2, 7, 7, 5, 3, 5, 1, 7, 8, 6, 7], after that print the list and than print an output.

3 0
3 years ago
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