Answer:
B ; C ; D
Step-by-step explanation:
Number of faces on a number cube = 6
Sample space = (1, 2, 3, 4, 5, 6)
P(1 then 0)
P(1) = 1/6 ; P(0) = 0
P(1 then 0) = 1/6 * 0 = 0
P(even number then odd number) :
P(even number) = 3/6 = 1/2
P(odd) = 3/6 = 1/2
P(even number then odd number) = 1/2 * 1/2 = 1/4
P(6 then 2) :
P(6) = 1/6 ; P(2) = 1/6 = 1/2
P(6 then 2) = 1/6 * 1/6 = 1/36
P(even number then 5) :
P(even) = 3/6 = 1/2
P(5) = 1/6
P(even number then 5) = 1/2 * 1/6 = 1/12
P(odd number then 2) :
P(odd) = 3/6 = 1/2
P(2) = 1/6
P(odd number then 2) = 1/2 * 1/6 = 1/12
You can not solve for a as all of the numbers are unknown
Answer: a=36; b=18
Step-by-step explanation:
1. You know that the sum of two numbers is 54, then, you have:
a+b=54
2. According to the problem, the larger number is 18 more than the sampler number, this can be expressed as following:
a=b+18
3. Then, you must substitute the second equation into the first equation and solve for b:
b+18+b=54
b=18
4. Then the value of a is:
a+18=55
a=36
To solve this problem we would plug 58 into the equation for a
Making the equation 59÷58
59÷58=1.0172413793103
Or
1.02
