Answer:
141.5 in
Step-by-step explanation
AB // CD // EF
12 / 15 = 21 / y (By the property of 3 parallel lines and its transversals)
y = (15*21) / 12 = 26.25
CD // EF // GH
21 / y = x / 10 21 / 26.25 = x / 10
x = (21*10) / 26.25
x = 8
perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5
Answer:
Step-by-step explanation:
Answer:
d> -8
:)
Step-by-step explanation:
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QRST is a rhombus
Let’s look at the diagonals
Length QS = sr(4^2 + 0) = 4
Length RT = sr(0 + 6^2) = 6
This means it cannot be a square or rectangle as they both have equal length diagonals.
QS is horizontal (y values same)
RT is horizontal (x values same)
This means it is a rhombus because diagonals are perpendicular and different lengths.
Squares have perpendicular diagonals of same length
Rectangles have diagonals of same length but not perpendicular
