Answer:
Question 1: y = 3/4x + 1/4.
Question 2: y = 6/5x + 7/5.
Step-by-step explanation:
Question 1: A line perpendicular to another line would have a slope that is the negative reciprocal of the other line. If the slope of the first line is -4/3, the slope of a line perpendicular to the first would have a slope of 3/4.
Since the line goes through (5, 4), we can just put the points into the equation, y = 3/4x + b.
4 = 3/4(5) + b
b + 15/4 = 4
b = 16/4 - 15/4
b = 1/4
So, the equation of the line is y = 3/4x + 1/4.
Question 2: 5x + 6y = -6
6y = -5x - 6
y = -5/6x - 1
As stated before, a line perpendicular to another will have a slope that is the negative reciprocal of the other. So, the slope of the other line is 6/5.
The line goes through (-2, -1), so we can put the points into the equation, y = 6/5x + b.
-1 = 6/5(-2) + b
b - 12/5 = -5/5
b = -5/5 + 12/5
b = 7/5
So, the equation of the line is y = 6/5x + 7/5.
Hope this helps!
If f(x) = 2x - 5 and g(x) = x + 52, then f(g(x)) can be deduced by placing g(x) in the spot of x in the f(x) equation as follows:
f(g(x)) = 2(g(x)) - 5
Since we know g(x) = x + 52, let's plug it in:
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
Answer:
the domain of a v-shaped graph is set of all real numbers
Step-by-step explanation:
Me too maybe b I just need some answers
