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vova2212 [387]
4 years ago
15

I have a test to do today and I need help with it, i don't understand any of it. I will copy and paste it here: IQ scores are no

rmally distributed with a mean of 100 and standard deviation of 15. 1) About what percent of people would have IQ between 85 and 115? 2) About what percent of people would have IQ between 70 and 130? 3) About what percent of people would have IQ above 130? 4) If a school had 255 students, about how many would you expect to have an IQ less than 70? 5) If a school had 1531 students, about how many would you expect to have an IQ greater than 145? 6) If a school has 354 students with an IQ between 100 and 130, about how many students does the whole school have?
Mathematics
1 answer:
tresset_1 [31]4 years ago
6 0

Answer:

68%

Step-by-step explanation:

IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. About 68% of individuals have IQ scores in the interval 100 ± 1 ( 15 ) = [ 85 , 115 ] .

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Answer:

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Step-by-step explanation:

(4+(4*3))*2=32

4*(4*3)=48

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If you multiply two even numbers where the product be even or odd explain with an example
dybincka [34]

Answer:

Even

Step-by-step explanation:

Any two numbers you multiply together that are both even will always result in an even number. For example 48x24=1152. You can use any two even numbers and you will always get and even product.

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What math do you mainly need to know in 7th grade
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Read 2 more answers
A gallup survey indicated that 72% of 18- to 29-year-olds, if given choice, would prefer to start their own business rather than
Neko [114]

Answer:

The probability that no more than 70% would prefer to start their own business is 0.1423.

Step-by-step explanation:

We are given that a Gallup survey indicated that 72% of 18- to 29-year-olds, if given choice, would prefer to start their own business rather than work for someone else.

Let \hat p = <u><em>sample proportion of people who prefer to start their own business</em></u>

The z-score probability distribution for the sample proportion is given by;

                               Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, p = population proportion who would prefer to start their own business = 72%

            n = sample of 18-29 year-olds = 600

Now, the probability that no more than 70% would prefer to start their own business is given by = P( \hat p \leq 70%)

       P( \hat p \leq 70%) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } \leq \frac{0.70-0.72}{\sqrt{\frac{0.70(1-0.70)}{600} } } ) = P(Z \leq -1.07) = 1 - P(Z < 1.07)

                                                                       = 1 - 0.8577 = <u>0.1423</u>

The above probability is calculated by looking at the value of x = 1.07 in the z table which has an area of 0.8577.

3 0
4 years ago
Solve y∕2.5 = 5 for y.
Radda [10]

Answer:

D)12.5

Step-by-step explanation:

y/2.5=5

y=5*2.5

y=12.5

5 0
3 years ago
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