A rancher with 750 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to
one side of the rectangle. 1] Find a function that models the total area of the four pens. (Let w be the width of the rectangular area and A(w) be the area.)
2]Find the largest possible total area of the four pens. (Round your answer to one decimal place.)
2 W + 5 L = 750 ft 5 L = 750 - 2 W L = 150 - 2 W / 5 A ( W ) = W * ( 150 - 2 W / 5 ) A function that models the total area: A ( W ) = 150 W - 2 W² / 5 A` ( W ) = 150 - 4 W / 5 150 - 4 W / 5 = 0 4 W / 5 = 150 W = 187.5 ft The largest possible area: A = 150 * 187.5 - (2 * 187.5² ) / 5 = 28,125 - 14,062.5 = 14,062.5 ft²
First, we know L and W are the same number. The in the end the Length is 6 more, therefore we add 6. The equations begins as so 2x+6=27 -6 2x=21 /2 x=10.5 +6 Therefore the Width =10.5 M The Length = 16.5 M
