1. BC is 1+3=4 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.
6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)
Answer:
9/4
Step-by-step explanation:
2 1/4 = 9/4 From mixed fraction to an improper fraction: "the numerator of the improper fraction" = "denominator" xx "the whole number" + "the numerator of the mixed fraction" The denominator remains as it is. So 2 1/4 = (4 xx 2 + 1)/4 = 9/4
Answer: 2y + 3x = -8.
Step-by-step explanation:
Given our first equation 2x-3y =13, we rewrite in the form of equation of a line, i.e y = mx + c
Where m is the slope of the line and c is the intersection on y axis.
By rewriting, we have...
3y= 2x-13
y= 2x/3 - 13/3.
m= 2/3, c= -13/3.
For two perpendicular lines, the product of their gradients is -1
i.e
m¹ * m² = -1
Hence m² = -1 * 3/2
m² = -3/2.
Hence, to get the equation of the line passing through the point (-6,5) we first find the intersection when x=0 given as
[Y-c]/[x-0] = -3/2
2y - 2c = -3x
2(5) - 2c =- 3(-6)
10-18= 2c
C = -8/2
C= -4
Then the equation is given as
y = mx + c
y = [-3/2]x - 4
2y= -3x - 8
2y + 3x = -8.
Wouldn’t it just be (0,0) ?
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