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Alinara [238K]
3 years ago
9

WILL GIVE BRAINLEIST : A party hat is in the shape of a cone. What is the volume of the hat in cubic centimeters?​

Mathematics
1 answer:
Brut [27]3 years ago
7 0
36xpi or 113.1 cm^3
hope that helped!! :)
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2x+1=2x-1<br> please help asap
lbvjy [14]

Answer:

do we have to simplify it ??

4 0
2 years ago
Each side of a rectangular prism measures 2 inches, and the height is 10 inches. What is the volume?
Diano4ka-milaya [45]
V=lwh
evidently, l=w=2

so
h=10
l=2
w=2

v=2*2*10=40

answer is 40 in^3
6 0
3 years ago
What is 0.128 as a fraction​
jekas [21]

0.128 \\  =  \frac{128}{1000}  \\  =  \frac{16}{125}

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0
2 years ago
Read 2 more answers
William has a lemonade stand. It costs him $0.30 to make 3 cups of lemonade. Find the rate of change of his cost and respect to
Snowcat [4.5K]

Answer:

I'm a bit confused, but it would cost $1.20 to make a dozen cups of lemonade

Step-by-step explanation:

0.30 divided by 3 is 0.10, and a dozen is twelve which makes the problem 0.10x12 which equals $1.20

8 0
3 years ago
Please help? I’m super lost...
babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function.  Watch and see.

a.  sin2\theta =-\frac{\sqrt{3} }{2}

Take the inverse sin of both sides.  When you do that, you are left with just 2theta on the left.  That's why you do this.

sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )

This simplifies to

2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2.  Those are:

2\theta =\frac{5\pi }{6} and

2\theta=\frac{7\pi }{6}

Divide both sides by 2 in both of those equations to get that values of theta are:

\theta=\frac{5\pi }{12},\frac{7\pi }{12}

b.  tan(7a)=1

Take the inverse tangent of both sides:

tan^{-1}(tan(7a))=tan^{-1}(1)

Taking the inverse tangent of the tangent on the left leaves us with just 7a.  This simplifies to

7a=tan^{-1}(1)

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1.  They are:

7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}

Dibide each of those equations by 7 to find that the values of alpha are:

\alpha =\frac{5\pi}{28},\frac{\pi}{28}

c.  cos(3\beta)=\frac{1}{2}

Take the inverse cosine of each side.  The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems.  That simplifies to:

3\beta=cos^{-1}(\frac{1}{2})

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

3\beta =\frac{\pi}{6},3\beta  =\frac{5\pi}{6}

Divide each of those by 3 to find the values of beta are:

\beta =\frac{\pi }{18} ,\frac{5\pi}{18}

d.  sec3\alpha =-2

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

\frac{1}{cos(3\alpha) } =\frac{-2}{1}

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

cos(3\alpha)=-\frac{1}{2}

Now we will take the inverse cos of each side (same as above):

3\alpha =cos^{-1}(-\frac{1}{2} )

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

3\alpha =\frac{7\pi}{6},3\alpha  =\frac{11\pi}{6}

Dividing both of those equations by 3 gives us

\alpha =\frac{7\pi}{18},\frac{11\pi}{18}

And we're done!!!

8 0
2 years ago
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