Please help due now

I don't know how to solve this. help please?

iragen [17]

Answer:

51 74

Step-by-step explanation:

x = smaller

x +23 = larger

added together (x + x+23) equal to 28 less than 3x = 3x-28

x + x+23 = 3x-28 subtract 2x from both sides of the equation

23 = x -28 add 28 to both sides

51 = x then the larger = 51 + 23 = 74

8 0

2 years ago

Read 2 more answers

Does anyone know how to do this?? steps are helpful but not necessary

aniked [119]

Answer:

C. $\frac{2(x+16)}{x+4}$

Step-by-step explanation:

We want fg of x, so first we have to multiply f(x) times g(x).

$\frac{x+16}{x} * \frac{2x}{x+4}$

$\frac{(x+16)2x}{x(x+4)}$

$\frac{2x^{2}+32x}{x^{2}+4x}$

We can cancel out an x from every term.

$\frac{2x+32}{x+4}$

Let's rewind a little to get this into one of the answer choices.

$\frac{2(x+16)}{x+4}$ is our answer.

6 0

3 years ago

Help pls quick i need the answer pls

fomenos

Answer:

multicultural

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

4. Bradford hopped into his Ford Mustang GT to rush to Diana and tell her

OLEGan [10]

Answer:

See explanation and image attached

Step-by-step explanation:

Acceleration refers to the rate of change of speed with time. We can see that between 0 and 4.7 seconds he accelerated quickly . That means that the rate of change of speed with time was greatest between 0 and 4.7 seconds.

A graph of the motion is shown in the image attached. We can see that he maintained a constant speed after 4.7 seconds.

5 0

2 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago