What is the center of a circle with the equation (x − 6)2 + (y + 2)2 = 9?

Mathematics

1 answer:

dedylja [7]2 years ago

4 0

Answer:

centre = (6, - 2 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 6)² + (y + 2)² = 9 ← is in standard form

with (h, k ) = (6, - 2 ) ← centre

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