Ask question

Ask question

All categories

2 years ago

11

Find the missing number. 19582 = 19000 +_+3

1 answer:

Kitty [74]2 years ago

3 0

Pancakes 7 it’s 7 pancakes

You might be interested in

The front of a tent is an equilateral triangle with the ratio of its base, b, to its height, h, given by b/h=2/√ 3 . Which equat

Agata [3.3K]

Picturing the tent helps, but we can actually solve this question using simple algebra and no knowledge of triangles.
The key is this function:
(b/h) = 2/√3
We want to get h by itself. First, multiply both sides by h:
b = h(2/√3) Now multiply both sides by the reciprical, (√3/2)
(√3/2) b = h

Therefore, the answer is C) h= b(√3/2)

3 0

3 years ago

a recipe for lemonade calls for 1 cup of sugar and 5 cups of water.How much sugar is used per cup of water

Kryger [21]

With one cup of sugar, you need five cups of water. For one cup, you divide one by five, which would be 1/5 cups of sugar.

6 0

3 years ago

Read 2 more answers

Find the area of the figure.

antiseptic1488 [7]

Answer:

area is 192

Step-by-step explanation:

yw

4 0

2 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

a

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

b

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

2 years ago

On the first math test, Keiko answered 19 out of 25 questions correctly. On the second test she got 17 out of 20 correct. On whi

jenyasd209 [6]

Answer:

shegot a better score on the second test

50 is double of 25

75is 3 times 25

100 is 4 times 25

Step-by-step explanation:

19 times 4= 76

17 times 5= 85

7 0

3 years ago