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Yanka [14]
2 years ago
12

Pls could someone help me with this​

Mathematics
1 answer:
kicyunya [14]2 years ago
3 0

Answer:

- Bar Gaps should be the same

Y-axis up in units of 5 would help out

Step-by-step explanation:

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gulaghasi [49]
C. Alternate interior angles are formed by a transverse line intersecting two parallel lines . They are located between the two parallel lines but on opposite sides of the transverse line
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1 year ago
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Which graph represents a proportional relationship?
dalvyx [7]

Answer:

Step-by-step explanation:

The first one as it is a sloping straight  passing through the origin.

3 0
2 years ago
Express the following vector in the form v=v1i+v2j+v3k. 3u - v if u=(4,7,-3) and v=(2,-7,5).3u - v = ____ i + ____ j + _____ k.(
Alecsey [184]

Answer:

<h2><em>5i+14j-7k</em></h2>

Step-by-step explanation:

Given the vectors u = (4,7,-3) and v=(2,-7,5), both vectors are 3-dimensional in nature and can also be rewritten as;

u = 4i+7j-3k and v = 2i-7j+5k

To get 3u-v, we will substitute the given vectors into the expression;

3u-v = 3(4i+7j-3k) -  (2i-7j+5k)

open the parenthesis

3u-v = 12i+21j-9k - 2i + 7j - 5k

collect like terms

3u-v = (12i - 2i) + (21j + 7j) (-9k-5k)

3u - v = 10i+28j-14k

To simplify the answer, we will divide through by 2

3u - v = 10i/2+28j/2-14k/2

<em>3u - v = 5i+14j-7k</em>

<em>Hence the simplified form of the expression is 5i+14j-7k</em>

3 0
2 years ago
Dose someone know how to figure this out can someone pleas help its a test
riadik2000 [5.3K]

Complete question is;

The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. In the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

Which equation can be used to find y, the year in which both bodies of water have the same amount of mercury?

A) 0.05 – 0.1y = 0.12 – 0.06y

B) 0.05y + 0.1 = 0.12y + 0.06

C) 0.05 + 0.1y = 0.12 + 0.06y

D) 0.05y – 0.1 = 0.12y – 0.06

Answer:

Option C: 0.05 + 0.1y = 0.12 + 0.06y

Step-by-step explanation:

In the first body, the initial measure of mercury is 0.05 parts per billion (ppb) while it's rising at a rate of 0.1 ppb each year. We are told to use y for the number of years.

Thus, amount of mercury for y years in this first body is;

A1 = 0.05 + 0.1y

Now, for the second body, we are told that;the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

Thus, amount of mercury for y years in this second body is;

A2 = 0.12 + 0.06y

Since we want to find the year in which both bodies of water have the same amount of mercury. Thus, it means;

A1 = A2

Thus;

0.05 + 0.1y = 0.12 + 0.06y

7 0
2 years ago
One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o
mezya [45]

Answer:

I don't know while not enquire from others

8 0
2 years ago
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