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Strike441 [17]
3 years ago
9

An 8-meter length connects the triangular front and back of a house roof. The base of the front

Mathematics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

B=3.6h

Step-by-step explanation:

I had the same question on my hw and I guessed that and got it right so

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Find all the real square roots of 0.0064
LenKa [72]
√64 = 8

64÷1000 = 0.0064

8÷1000=0.0008

√0.0064 = 0.0008
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3 years ago
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Complete the equation of the line whose slope is -2 and y-intercept is (0,3)<br><br> Please help!
Maslowich
It’s a no solution problem
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Line GH contains points G(–2, 6) and H(5, –3). Given the points, what is the slope of the line ?.
IRINA_888 [86]
The slope is m = rise/run
m = ( -3 - 6 ) / ( 5 - ( -2 )) = -9 / ( 5 + 2 ) = - 9/7
Answer: the slope of the line is -9/7.
6 0
3 years ago
Read 2 more answers
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
Whats the cost of each vegetable if 5 squash and 2 zucchini is $1.32​
alex41 [277]

Answer:

Step-by-step explanation:

 

We first need to define a couple of variables.  Let s = the cost of 1 squash and z = the cost of 1 zucchini.

 

Now lets translate the words into algebra:

 

"The cost of 5 squash and 2 zucchini is $1.32"  ===>  5s  +  2z  =  1.32

 

"Three squash and 1 zucchini cost $0.75"  ===>   3s  +  z  =  0.75

 

There are several ways to solve systems of equations.  Let's use substitution.  We can find what z equals in terms of s by manipulating the second equation:

 

 3s  +   z   =   0.75

-3s                 -3s

------------     -------------

           z    =  -3s  +0.75

 

Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:

 

 5s + 2(-3s + 0.75) = 1.32

 

Can you handle it from here?

 

(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)

3 0
3 years ago
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