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makvit [3.9K]
3 years ago
9

"absmiddle" class="latex-formula">
Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0
(b-c)x(b+c-10)

hope this helps

tino4ka555 [31]3 years ago
5 0
It its to factor b^2-c^2-10b+10c
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What is the equation of the line that passes through each pair of points in slope-intercept form?
Ivanshal [37]
First, you need to use the points to come up with a m (slope). To do this you must use the equation m= y2-y1/x2-x1. label the x in one pair of coordinates x1 and the y, y1. Then label the other x in the other pair of coordinates x2 and the y, y2. use the equation and figure the slope. Next, put the easiest coordinates into point-slope form. The equation you are to use is... y-y1=m(x-x1). Input the values and then distribute the m inside the parenthesis. Then you should be able to do the rest. The final product should be in slope-intercept form. 
6 0
3 years ago
Could someone help me bc idkk how this works
dmitriy555 [2]

Answer:

the answer is 2.

Step-by-step explanation:

This is because the interest rate is if he had $1 in the account for a year you would add the 18% or in decimel form 0.0018 do that to the 15th to get 15 years and multiply that by 5000 because that was the ammount of money he put in so 5000(1*0.0018)15 or 0.0018^15*5000

5 0
3 years ago
An office manager estimates that she spends 40% of her 30-minute lunch
Elina [12.6K]

Answer:

answer = 12 min

Step-by-step explanation:

40% of 30 min = ?

10% of 30 min = 3

3*4 = 12

Thus, she spends 12 min of her 30 min lunch driving

P.S.

If the answer is wrong, then multiply it by two and retry

4 0
3 years ago
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








7 0
3 years ago
Bubba Bulldog and all of his dog friends love to hide bones! Bubba hid 4 bones, Barry hid 5 bones, Larry hid 10 bones, and Goby
JulsSmile [24]

Answer:8

Step-by-step explanation:

You find the average which is adding them all together then dividing by how many numbers you added.

6 0
3 years ago
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