Write a program for determining if a year is a leap year. In the Gregorian calendar system you can check if it is a leaper if it
1 answer:
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Answer:
Following are the correct python code to this question:
n1 = float(input('Input first number: '))#input first number
n2 = float(input('Input second number: '))#input second number
n3 = float(input('Input third number: '))#input third number
n4 = float(input('Input fourth number: '))#input fourth number
average = (n1+n2+n3+n4)/4 #calculate input number average
product = n1*n2*n3*n4 # calculate input number product
print('product: {:.0f} average: {:.0f}'.format(round(product),round(average))) #print product and average using round function
print('product: {:.3f} average: {:.3f}'.format(product,average)) #print product and average value
Output:
Please find the attachment.
Explanation:
The description of the above python code can be defined as follows:
- In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
- In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
- In the last line, the print method is used, which prints its variable value by using a round and format method.
