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Burka [1]
3 years ago
15

Which one of the statements best characterizes the current state of e-commerce?

Computers and Technology
1 answer:
svlad2 [7]3 years ago
6 0

It has been rapidly expanding over the last several years and is expected to continue to expand at an even faster rate.

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Step 1: Configure the initial settings on R1. Note: If you have difficulty remembering the commands, refer to the content for th
Andru [333]

Answer:

The configuration of the R1 is as follows

Explanation:

Router>enable

Router#show running-config

Router#show startup-config

Router#configure terminal

Router(config)#hostname R1

R1(config)#line console 0

R1(config-line)#password letmein

R1(config-line)#login

R1(config-line)#exit

R1(config)#enable password cisco

R1(config)#enable secret itsasecret

R1(config)#service password-encryption

R1(config)#banner motd #Unauthorized access is strictly prohibited#

R1(config)#end

R1#exit

R1>enable

R1#copy running-config startup-config

R1#show flash

R1#copy startup-config flash

3 0
3 years ago
What happens when variables in programming are not properly initialized? answers?
Romashka-Z-Leto [24]
Errors in compilation happen, or it runs but then doesn't recognize the input. Also you can't transform into other types of variables.
6 0
3 years ago
What are the four conditions to help determine whether a website is a good source for information?
Ratling [72]

Answer:

1. Credible Websites are Registered with Legitimate Institutions 2. Watch out for Dummy Content for Website Credibility Check 3. Watch out for Scam Advertisements to Verify Website Credibility 4. Professional Designs Mean Everything

Explanation:

3 0
2 years ago
Assume the system with 256B memory and 64B cache and the block size of 16 bytes. I.e., there are 4 blocks in the cache. (a) For
Nataliya [291]

Answer:

Check the explanation

Explanation:

1.

System = 256Byte = 8 bit

Cache = 64B , block size = 16 byte.

A) Direct Mapped Cache:

Block offset = log (Block size) = log 16 = 4bit

Total # of block inside cache = 4.

Therefore index offset = log 4 = 2bit.

Remaining is tag bits.

Therefore tag bits = 8-(4+2) = 8-6 = 2 bits

Tag                              Index offset                                Block offset

(2 bits)                             (2 bits)                                           (4 bits)

Fully associative cache :

In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.

Therefore tag bits = 8-block offset bit= 8-4 =4bits

Tag                               Block offset

(4 bits)                                (4 bits)

4 0
3 years ago
In full verbatim, a person wants to say that they admitted him to a hospital last month. He makes a mistake about the date and q
MA_775_DIABLO [31]
He should cancel the date and move to another country semis how he screwed up his work, hope this helped
3 0
3 years ago
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