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Rzqust [24]
3 years ago
13

Janet can do a job in three hours while Gary can do the same job in two hours. If Janet works for an hour before Gary be in help

ing her how long will it take them to finish the job together?
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
6 0

Janet = 1/3

Gary = 1/2

(1/3) + (1/2) = 5/6

Let x = time they both can do the job together

(1/2) + (5/6)x = 1

Solve for x to find your answer.

Oxana [17]3 years ago
6 0

Answer:

Janet = 1/3

Gary = 1/2

(1/3) + (1/2) = 5/6

Let x = time they both can do the job together

(1/2) + (5/6)x = 1

Solve for x to find your answer.

Step-by-step explanation:

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Estion
dalvyx [7]

Using the Poisson distribution, it is found that there is a 0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

Considering the average of 15 birds every 2 hours during daylight hours, the mean for a 45-minute period is given by:

\mu = 15 \times \frac{45}{120} = 5.625

The probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours is given by:

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.625}(5.625)^{0}}{(0)!} = 0.004

P(X = 1) = \frac{e^{-5.625}(5.625)^{1}}{(1)!} = 0.02

P(X = 2) = \frac{e^{-5.625}(5.625)^{2}}{(2)!} = 0.057

P(X = 3) = \frac{e^{-5.625}(5.625)^{3}}{(3)!} = 0.107

P(X = 4) = \frac{e^{-5.625}(5.625)^{4}}{(4)!} = 0.150

P(X = 5) = \frac{e^{-5.625}(5.625)^{5}}{(5)!} = 0.169

Then:

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.004 + 0.02 + 0.057 + 0.107 + 0.15 + 0.169 = 0.507

0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

3 0
1 year ago
Which correctly applies the distributive property to show an equivalent expression to (8.6)(–2.5)?
PSYCHO15rus [73]
We see all of them have 2 and 0.5
so therfor b+c=-2.5

so

remember
a(b+c)=ab+ac
so
8.6(-2-0.5)=8.6(-2)+8.6(-0.5)


last option
7 0
3 years ago
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