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3 years ago

Use the figure at the right to name the following.

Mathematics

1 answer:

viva [34]3 years ago

6 0

$\large\huge\green{\sf{Answer:-}}$

two acute angle=<JBC and <JBG

<JBC and <JBG(because these two angle are 45°)

by definition of acute angle any angle which is between 0°to 90° then it will acute angle

two straight line=FH ,.AD
two right angle=<GBD and <GBA
two obtuse angle=<BCH and <BGF

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A bag contains 50 lottery balls, numbered 1-50. A ball is chosen at random, then a month of the year is selected. What is the pr

Morgarella [4.7K]

Answer:

4/75

Step-by-step explanation:

We have two sample spaces

1.Lottery balls

2. Month of the year

For lottery balls the sample space is S= 50

Multiples of 3 between 1 and 50 are

(3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48)= 16 in numbers

Hence the probability of choosing a multiple of 3

Pr(multiple of 3) = 16/50= 8/25

Also the sample space for months of the year is S= 12

Two months starts with letter m, March and may

Pr(of months with m) = 2/12= 1/6

the probability of choosing a multiple of 3 and a month starting with the letter M= 8/25*1/6= 8/150= 4/75

6 0

4 years ago

Give the domain and range. domain: {2, 0, 2}, range: {1, 0, 1}

Leona [35]

<h2>Domain: {0, 2}</h2><h2>Range: {0, 1, 1}</h2><h2 /><h3>When dealing with the domain, remember that no numbers can repeat in the domain so if there is more than one of the same number, we only list it one.</h3><h3 /><h3>When dealing with the range, it's ok if numbers repeat because it's the y-value not the x-value.</h3><h3 /><h3 />

5 0

3 years ago

Find the measure of angle2<br><br> A. 90<br> B. 50<br> C. 60<br> D. 30

galina1969 [7]

I think it is C. 60.
You can eliminate A because it is not a right angle, and D because the angle is bigger than the given angle. So it is between 50 and 60, and I hope this is right and the picture makes sense

6 0

3 years ago

Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N

miskamm [114]

Answer:

114°

Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

<h3>setup</h3>

(11x +15)° = 60° +6x°

<h3>solution</h3>

5x = 45 . . . . . . . . . divide by °, subtract 15+6x

x = 9 . . . . . . . . . . divide by 5

The measure of exterior angle KMN is ...

m∠KMN = (11(9) +15)° = 114°

_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

60° +6x° +M = 180°

(11x +15)° +M = 180°

Equating these expressions for 180° and subtracting M gives the relation we used above:

(11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°

(11x +15)° = 60° +6x° . . . . . . . . . . . subtract M

This is also described by "supplements to the same angle are equal."

4 0

2 years ago

Read 2 more answers

Can you guys help we with this question.

satela [25.4K]

Answer:

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

4 0

3 years ago

Read 2 more answers