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2 years ago

Use the figure at the right to name the following.

Mathematics

1 answer:

viva [34]2 years ago

6 0

$\large\huge\green{\sf{Answer:-}}$

two acute angle=<JBC and <JBG

<JBC and <JBG(because these two angle are 45°)

by definition of acute angle any angle which is between 0°to 90° then it will acute angle

two straight line=FH ,.AD
two right angle=<GBD and <GBA
two obtuse angle=<BCH and <BGF

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If their is a cube with 2/3ft what is the surface area?

Arlecino [84]

A cube has 6 sides.

Find 1 side:
1 side = 2/3 x 2/3 = 4/9

Find 6 sides:
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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap

11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=20$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20$

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

$h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)$

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

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2 years ago

On a sunny day, a flag pole and its shadow form the sides of a right triangle. if the hypotenuse is 35 meters long and the shado

Triss [41]

We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!

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2 years ago

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Lelu [443]

If you know that b=0, then ab=bc doesn't tell you anything about
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3 years ago