Let C(x) = -0.75x + 20,000 and R(x)= -1.50x then the profit function exists noted as P(x) = R(x) - C(x)
P(x) = -1.50x - (-0.75)x + 20,000
P(x) = -0.75x + 20000
Therefore, the profit function exists -0.75x + 20000.
<h3>How to find profit function?</h3>
The profit function can be estimated by subtracting the cost function from the revenue function. Let profit be expressed as P(x), the revenue as R(x), the cost as C(x), and x as the number of items traded. Then the profit function exists noted as P(x) = R(x) - C(x).
Given:
C(x) = -0.75x+20,000 and R(x)= -1.50x
P(x) = R(x) - C(x)
= -1.50x - (-0.75)x + 20,000
= -1.50x + 0.75x + 20,000
Apply rule -(-a) = a
= -1.5x + 0.75x + 20000
Add similar elements:
-1.5 x + 0.75x = -0.75x
P(x) = -0.75x + 20000
Therefore, the profit function exists -0.75x + 20000.
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Answer:
z (min) = 705
x₁ = 10
x₂ = 9
Step-by-step explanation:
Let´s call x₁ quantity of food I ( in ou ) and x₂ quantity of food II ( in ou)
units of vit. C units of vit.E Cholesterol by ou
x₁ 32 9 48
x₂ 16 18 25
Objective function z
z = 48*x₁ + 25*x₂ To minimize
Subject to:
1.-Total units of vit. C at least 464
32*x₁ + 16*x₂ ≥ 464
2.- Total units of vit. E at least 252
9*x₁ + 18*x₂ ≥ 252
3.- Quantity of ou per day
x₁ + x₂ ≤ 35
General constraints x₁ ≥ 0 x₂ ≥ 0
Using the on-line simplex method solver (AtoZmaths) and after three iterations the solution is:
z (min) = 705
x₁ = 10
x₂ = 9
Saturday night after the marshmallows ran out, the counselor
threw 30 cold stones on the campfire, and sent the campers
to bed in their tents.
But several campers noticed that there were still live coals in
the fire. This was a tent situation, and they knew that they
should not leave until it's completely out. So they each
picked up 10 cold stones and they all threw those on the fire
too. Then the fire was really out, so they all went to their tents.
In the morning the same campers who threw 10 stones apiece
onto the fire all got together and went to look at it. It was definitely
stone cold, so they spread it out and counted all the stones in it.
They found that there were exactly 100 stones. How many
campers threw stones on the fire after the counselor left ?
The difference is +3.
You move from -6 to -5 to -4 to -3.
That’s 3 units of difference.
Answer:
Step-by-step explanation:
Assuming the rate of increase in the cost of tuition fee per year is linear. We would apply the formula for determining the nth term of an arithmetic sequence which is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500(amount in 2000)
From 2000 to 2018, the number of terms is 19, hence,
n = 19
T19 = 454120
Therefore,
454120 = 20500 + (19 - 1)d
454120 - 20500 = 18d
18d = 433620
d = 433620/18
d = 24090
Therefore, the equation that can be used to find the tuition y for x years after 2000 is expressed as
y = 20500 + 24090(x - 1)
To to estimate the tuition at this college in 2020, the number of terms between 2000 and 2020 is 21, hence
x = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
