9. Ellie is making a batch of pancakes

Mathematics

1 answer:

Vikki [24]3 years ago

4 0

Answer:

Step-by-step explanation:

Maybe your questions has some wrong numbers in it? but, going by what's in your questions , just 1 cup of flour :/ seems too easy

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The u.s. dairy industry wants to estimate the mean yearly milk consumption. a sample of 16 people reveals the mean yearly consum

lidiya [134]

1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.

3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75

4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)

5. Since the interval include 63, it is reasonable.

3 0

3 years ago

Subtract. Write your answer in simplest form.<br> 5/- 10/5

tigry1 [53]

Answer:

-1/10

Step-by-step explanation:

(5/(-10))/5 = -(5/10)/5 = 1/10

(Hopefully this helped you out!)

7 0

3 years ago

How do u do b??????????

horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

if she uses and input of 6 on the 2nd one, the result will be 6² - 6 = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

clearly we can never get an output of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

$\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x$

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

$\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x$

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

$\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5$