1. The probability that we select a red marble is 1/3.
We found this out by taking the amount of red marbles there are and the total amount of marbles. The total amount of marbles is 18 and there are red marbles. So, it would become 6 out of 18 or 6/18. Then, we simplify 6/18 to the simplest form. The greatest common factor of both of those numbers is 6. Lastly, we divide each of them by 6 to get the simplest form.
6/18 = (6/6)/(18/6)
(6/6)/(18/6) = 1/3
So, therefore, the theoretical probability of picking a red marble is 1/3.
2. The probability that we select a blue marble is 2/3.
We can find this out by taking the amount of blue marbles there are and the total amount of marbles. We know that the total amount of marble is 18 and there are 12 blue marbles. So, we simply get the GCF (greatest common factor) and divide them by it.
Greatest Common Factor of 12 and 18 = 6
12/18 = (12/6)/(18/6)
(12/6)/(18/6) = 2/3
Thus, the theoretical probability of picking a blue marble is 2/3.
{(-1,3),(-1,4),(-1,5),(-1,6)} is the set from the given question which is a set of ordered pairs representing a function.
<h3>What is ordered pair?</h3>
An ordered pair (a, b) in mathematics is a group of two things. The pair's order of objects matters because the ordered pair (a, b) differs from the ordered pair (b, a) unless a = b. (By contrast, an unordered pair of a and b equals an unordered pair of b and a.)
Ordered pairs are also known as 2-tuples, or sequences (or, in computer science, occasionally, lists) of length 2. Sometimes referred to as 2-dimensional vectors, ordered pairs of scalars. Technically speaking, this is a misuse of the term because an ordered pair need not be a component of a vector space. An ordered pair's entries may be other ordered pairs, allowing for the recursive definition of ordered n-tuples (ordered lists of n objects).
So if m=4a+2c is your equation then all you have to do is plug in the numbers.
So you then get m=4(25)+2(7), for 25 adults and 7 children.
Then you solve. m=100+2(7) m=100+14 m=114 So Frank will need 114 Meatballs for the party of 25 adults and 7 children Hope this helps! And if you need anything else just ask :)
