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laila [671]
3 years ago
10

Se Home

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0
It’s 20000 but not sure about it
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Please help! Show work!
Thepotemich [5.8K]

Answer:

the answer is im back and i dont know

Step-by-step explanation:

hi wanna talk i was rlly sick



4 0
3 years ago
A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

8 0
3 years ago
Please help me answer all parts of question 3 in the photo.
Nookie1986 [14]
(i.) CA = πrl
CA = π (5*13)
CA = 65π

(ii.) TA = πrl + πr^2
TA = 65π + π (5^2)
TA = 65π + 25π
TA = 90π

(iii.) To get the height of the cone, you have to use the Pythagorean theorem. Plug in the radius for a and the slant height for c.

a^2 + b^2 = c^2
5^2 + b^2 = 13^2
25 + b^2 = 169 Height = 12
b^2 = 144
b = 12

(iv.) v = (1/3)πr^2h
v = (1/3)π(5^2)*12
v = (1/3)π(25*12)
v = (1/3)π*300
v = 100π


5 0
3 years ago
PLEASE ANSWER ASAP. WILL GIVE BRAINLIEST
Eduardwww [97]

Answer:

I cant see that, its upside down.

Step-by-step explanation:

3 0
3 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0
3 years ago
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