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kakasveta [241]
3 years ago
5

Find the domain when f (x) = 5. х -5 -1 9 4 5 8 f(x) -6 -6 | 0

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

Pues la función de 5 seria 4 porque si te fijas en la X es (4)

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Therea re 8 kids at a birthday party. If there are 6 girls and 2 boys at the party, what draction of the kids are girls?
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3/4

Step-by-step explanation:

The total number of children is 8 and the number of girls is 6. This can be represented as 6/8.

You would then need to simplify...

6/2=3

8/2=4

which which lead you to 3/4!

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

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