The sum of three consecutive intergers is 267. What is the largest integer
2 answers:
Answer:
90
Step-by-step explanation:
Let the starting number be x, the two consecutive numbers after x is gonna be x+1 and x+2.
If the sum of these three numbers is 267 then:
x+(x+1)+(x+2)=267
Solve
3x+3=267
3x=267-3
3x=264
x=264/3
x=88
x+1=89
x+2=90
Your three consecutive numbers are 88, 89, and 90.
The largest one of them is 90.
Answer:
88+89+90=267
Step-by-step explanation:
To do this just divide 267/3 and you get 89, you just look for the previous number (88) and the top number (90) and the sums.
88.89.90
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