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Verdich [7]
3 years ago
14

Which of the following examples best represents the use of an interval scale? measuring the number of cookie boxes sold by scout

s on the west coast of a town versus those sold on the east coast of the town naming the different car brands seen in a school's parking lot assessing students' ratings of their professors' performance on a five-point scale ranging from poor to excellent ranking the participants of a race based on their performance
Mathematics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

students' ratings of their professors' performance on a five-point scale ranging from poor to excellent

Step-by-step explanation:

There are four type of scales in mathematics. They include:

1. Nominal scale : they do not measure quantity. they are used to classify a population into two or more scales that are exhaustive and mutually exclusive. e.g. classifying a population based on gender, naming the different car brands seen in a school's parking lot

2. Ordinal scale : this scale measures ranks a population from best to worst or from least to most. e.g. ranking the participants of a race based on their performance

3. Interval scale : this scale has the property of order and equal intervals. Zero is not meaningful.

Interval scale is used when the difference between the numbers are meaningful. e.g. students' ratings of their professors' performance on a five-point scale ranging from poor to excellent Here a child who is scored 1, did very poorly and a child scored 5, performed excellently well.

4. Ratio scale :  this scale has the property of order, a meaningful zero and equal intervals.

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A painting measures 15 cm long by 24 cm high. You buy two posters, each showing an enlargement of the painting. The first poster
Airida [17]

Answer:

The Answer Is C The fist poster is the proper representation, because find the areas compare the paintings to the first poster it is 360 to 3240 which shows the poster is 9x bigger but compared to the second one it is out of proportion for the painting and first poster

5 0
3 years ago
Find the length of x. help please !
andreyandreev [35.5K]

Answer:

x = 10

Step-by-step explanation:

Use CPCTC (Corresponding parts of congruent triangles are congruent).

Set the ratios:

\frac{6.5}{5} = \frac{6.5 + 6.5}{x}

First, simplify. Combine like terms:

\frac{6.5}{5} = \frac{13}{x}

Next, cross multiply.

5 * x * \frac{6.5}{5}  = \frac{13}{x} * x * 5\\x * 6.5 = 13 * 5\\6.5x = 65\\

Isolate the variable, x. Divide 6.5 from both sides of the equation:

\frac{(6.5x)}{6.5} = \frac{(65)}{6.5} \\\\x = \frac{65}{6.5}\\x =  10

Check:

\frac{5}{6.5} = \frac{x}{13}

Plug in 10 for x (Your answer). Cross multiply, then simplify:

\frac{5}{6.5} = \frac{10}{13}

13 * 6.5 * \frac{5}{6.5} = \frac{10}{13} * 13 * 6.5

13 * 5 = 10 * 6.5

65 = 65 (True).

~

6 0
3 years ago
What are the domain and range of the function y = –2(x – 4)² + 1?
neonofarm [45]

Answer: Domain: x = All Real Numbers (-∞, ∞)

              Range: y ≤ 1 (-∞, 1]

<u>Step-by-step explanation:</u>

y = -2(x - 4)² + 1

The equation is in vertex form → vertex = (4, 1)

The leading coefficient is negative so it will be a max at y = 1

Range: y ≤ 1.

This is a polynomial so there are no restrictions on x.

Domain: x = All Real Numbers

5 0
4 years ago
RIGHT ANSWER GETS BRAINLIEST NO LINKS Factor the square root.<br> √160
kipiarov [429]

Answer:

<h2>Factor perfect squares out of the square root until there are no more perfect squares inside.</h2>

Step-by-step explanation:

<h2>Begin by working inside the square root itself. You can manipulate the interior of the square root as much as you'd like so long as you don't violate any other rules of algebra. </h2>

<h2>√160=√16⋅10</h2>

<h2>Because 16 is a perfect square, we can pull it out of the square root as a 4.</h2>

<h2>That will simplify down to 4√10</h2>

<h2>because there are no additional perfect square factors in 10, the resultant is simplified.</h2>

<h2>Therefore, √160 simplifies to 4√10</h2>
3 0
3 years ago
What does the Exponential Decay Variables Mean?<br> For Half Lifes<br> Y=Ae^-bX
kompoz [17]
A is the initial population
 
b is the decay coefficient
 
X is normally the time.

Y = Ae^{-bx}

<span>then is the population half of the initial population of A
 
for half life you will have
</span>
\frac{Y}{A} = \frac{1}{2}

<span>so the equation becomes
</span>
\frac{1}{2} = e^{-bX}&#10;\\&#10;\\\ln{ \frac{1}{2}} =\ln{e^{-bX}}&#10;\\&#10;\\ \ln{1}-\ln{2}=-bX&#10;\\bX=\ln{2}




8 0
3 years ago
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