Answer:
AA similarity
Step-by-step explanation:
Using angle sum theorem, you can clearly find out the missing angles on the left and right triangles are 40° and 50° respectively.
Therefore, by using any two angles in the triangles, you can prove they are similar by AA similarity.
Answer:
Step-by-step explanation:
∵ When x is a random variable having distribution B(n, p), then for sufficiently large value of n, the following random variable has a standard normal distribution,
Where,
Here the variable X has a binomial distribution,
Such that, np (1 - p) ≥ 10 ⇒ n is sufficiently large.
Where, n is the total numbers of trials, p is success in each trials,
So, the mean of variable X is,
And, variance of variable X is,
sub x=1 into f(x),
remainder= 1^3+2(1)^2-5(1)-6= -8
since remainder≠0, x=1 is not a root of the function
sub x=-1,
remainder = (-1)^3+2(-1)^2-5(-1)-6= 0
by remainder theorem,
x=-1 is a root of f(x)
hence, the correct ans is c
For me, it’s easiest when i distribute the negative sign if i need to and then reorder to put the like terms together. and then solve.
(also sorry if it’s a little confusing with all the parentheses, i use them because it helps me organize everything)
21. (4x-9y) + (6x+10) + (8y-4)
= 4x + 6x - 9y + 8y + 10 - 4
= 10x - y + 6
—> D
22. (6x+9y-15) + (2x-9y+8)
= 6x + 2x + 9y - 9y - 15 + 8 (the 9y - 9y = 0, so you can leave it out of the final equation)
= 8x - 7
—> D
23. (9x^2-8x+3) - (5x^2-6x+4)
= 9x^2 - 8x + 3 - 5x^2 -(-6x) - 4
= 9x^2 - 5x^2 - 8x + 6x + 3 - 4 (remember that two - signs next to each other make a + sign)
= 4x^2 - 2x - 1
—> A
24. (9x^3-7x+8) - (5x^2+7x-10)
= 9x^3 - 7x + 8 - 5x^2 - 7x -(-10)
= 9x^3 - 5x^2 - 7x - 7x + 8 + 10
= 9x^3 - 5x^2 - 14x + 18
—> D
25. (6x+14y) - ((7x+5y) + (x-8y))
= (6x+14y) - (7x + x + 5y - 8y)
= (6x+14y) - (8x-3y)
= 6x + 14y - 8x -(-3y)
= 6x - 8x + 14y + 3y
= -2x + 17y
—> B
[tex]\begin{gathered} \text{The inequality is,} \\ 5
