Question

Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the weekend, plus $0.07 per mile. Divya only has $230. Write an inequality, solve, and determine her limitations when renting.

Answer 1

Answer:

$200 + 0.07m \leq 230$

A maximum of $\approx$ 428 miles is the distance what Divya can travel.

Step-by-step explanation:

Given that:

Rent to be paid for the car in the weekend = $200

Charges to be paid per mile = $0.07

Total money available  with Divya = $230

To find:

The inequality as per her limitations and solution to the problem.

Solution:

Let the number of miles for which Divya can drive = $m$ miles

Charges for one mile = $0.07

Charges for $m$ miles = $0.07$m$

Total charges for renting and $m$ miles = Rental charges + Operational charges

Total charges for renting and $m$ miles = $200 + $0.07$m$

These are charges must be lesser than equal to the amount of money available with Divya.

Therefore, we can write:

$200 + 0.07m \leq 230$

Subtracting 200 from both the sides:

$0.07m \leq 30$

Dividing both sides with 0.07:

$m \leq \dfrac{30}{0.07}\\m\leq 428.6$

Therefore, a maximum of $\approx$ 428 miles is the distance what Divya can travel.