It is 10 times as much as .008
Do you see the pattern?
Answer:
They are compatible
Step-by-step explanation:
The first thing is to say that an "ace" and that it is a "coarse"
"ace" is card number 1. Group A
"coarse" is a type of the deck, found from number 1 to card 13. Group B
Thus:
Calculate A U B:
1 to 13 + 1 of the other types of cards in the deck.
At intersection B:
1 of "coarse"
Therefore, if group A is compatible with group B
Answer:
Try your best! I know you can do it!
Answer:
The answer is 3/4
Step-by-step explanation:
look up scale factor calculator
a. By the chain rule,
h'(x) = f'(g(x)) * g'(x)
h'(1) = f'(g(1)) * g'(1) = f'(1) * 1 = 3
b. I suspect there's a typo here somewhere, but if you really mean j(x) = f(x), and you're only supposed to find j(1), then
j(1) = f(1) = 2
Possibly you're supposed to instead find j'(1), in which case
j'(1) = f'(1) = 3
Or maybe j is defined like
j(x) = 1/f(x)
in which case the chain rule gives
j'(x) = -f'(x)/f(x)^2
j'(1) = -f'(1)/f(1)^2 = -3/2^2 = -3/4
c. By the chain rule,
k'(x) = g'(x)/g(x)
k'(1) = g'(1)/g(1) = 5/1 = 5
