Well I know this is not linear becuase then the y-values would be going up by a constant number. So, B and C are gone. Personally, A looks a bid odd. So, If I were you I'd go with D.
Just my opinion, not 100%
Linear, decrease by 2 for every decrease of x.
Answer:
f(x) = 2x^2 - 3x + 1
Step-by-step explanation:
The root 1 is associated with the factor (x - 1).
The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)
The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:
f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1