Answer:
Pythagorean Theorem: c2 = a2 + b2
Find the area by adding the areas of the three triangles. The area of a right triangle is: A = ½bh
Two triangles are identical so you can just multiply the area of the first triangle by two: 2A1 = 2(½bh) = 2(½ab) = ab.
The total area of the trapezoid is : A1 + A2 = ab + ½c2
You multiply both sides by 2 to get rid of the ½: (a2 + 2ab + b2) = 2ab + c2
You subtract out the 2ab: a2 + b2 = c2.
Then what is left is the proof: a2 + b2 = c2
we have been asked to find the sum of the series

As we know that a geometric series has a constant ratio "r" and it is defined as

The first term of the series is 
Geometric series sum formula is

Plugin the values we get

On simplification we get

Hence the sum of the given series is
Answer:
You need to cross multiply 37/45+x/100 which equals 17%
Step-by-step explanation:
The first part represents the 37 dollars out of the original 45 and the second part represents x= the unknown percent out of 100 percent. This would be 17%