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3 years ago

Which statement correctly describes a net?

Mathematics

1 answer:

charle [14.2K]3 years ago

3 0

<h2>Answer:</h2>

A) A net is a two-dimensional pattern for a solid.

<h2>Step-by-step explanation:</h2>

In fact, a net is a two-dimensional pattern for a solid. But what is a solid? They are three-dimensional shapes. Prisms, cubes, pyramids, among others, are examples of solids. For example, the first figure below is a net because is a two dimensional patter for a pyramid which is shown in the second figure. As you can see, the first figure is a two-dimensional patter for this three-dimensional shape. Hence, by unfolding the pyramid we get the net or, in other word, by folding the net we get the pyramid.

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Solve 2 log3 x + log3 5 =125

zepelin [54]

Answer:

x = √(3^125/ 5)

approx 2.9552445 * 10^29.

Step-by-step explanation:

2 log3 x + log3 5 =125

log3 x^2 + log3 5 = 125

log3 (5x^2) = 125

3^125 = 5x^2

x^2 = 3^125/ 5

x = √(3^125/ 5)

This is a huge number

An approximation of it is 2.9552445 * 10^29.

3 0

2 years ago

10x + 4x 3 – 4 Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.

weqwewe [10]

Guessing that the 3 was suppose to be an exponent.

The answer written in standard form is :
4x^3 + 10x - 4

This is called a cubic trinomial.

7 0

2 years ago

Suppose the temp is -1 f and drops by 3 f. Explain how to use the number line to find the new temp

juin [17]

This is how you can find the solution

4 0

3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is<em> </em> $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, <em>the probability that a student has either a Visa card </em><em>or</em><em> a MasterCard is </em> $\\ P(V \cup M) = 0.88$ .<em> </em>

Are the events V and M independent?

A way to solve this question is by using the concept of <em>conditional probabilities</em>.

In Probability, two events are <em>independent</em> when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a <em>conditional probability</em> or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events <em>were independent</em>.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

3 years ago

What is 1/10 + 1/10 + 1/10

natali 33 [55]

3/10................

8 0

3 years ago

Read 2 more answers