Will give brainliest

camelback mountain has an elevation change of 1,264 feet. how many pennies would it take to make a stack that high ? show all wo

gtnhenbr [62]

Camel back Mountain = 15,168 inches (1,264 feet)

1 Penny = 0.061 (.0610) Inches

10 Penny = 0.61 (.610) Inches

100 Penny = 6.1 (6.10) Inches

1,000 Penny = 61 (61.0) Inches

10,000 Penny = 610 (610.0) Inches

-SOLVING-

10,000 Penny = 610 inches PLUS

1,000 Penny = 61 inches AND 61 inches x 5 = 305 (5,000 Penny)

100 Penny = 6.1 inches PLUS

10 Penny = 0.61 inches AND 0.61 inches x 6 = 3.66 (60 Penny)

1 Penny = 0.061 inches AND 0.061 inches x 8 = 0.488 (8 Penny)

-FINAL ANSWER-

610 + 305 + 6.1 + 3.66 + 0.488 = 925.248 Penny it would take.

3 0

2 years ago

If the measure of angle 2 is 92 degrees and the measure of angle 4 is (one-half x) degrees, what is the value of x?

zavuch27 [327]

Answer: x = 184°

Step-by-step explanation: As we can see in the figure below, angles 2 and 4 are Vertical Angles, i.e., they are angles opposite each other when two lines cross. Vertical angles are always congruent.

Then,

m∠2 = m∠4

$92=x.(\frac{1}{2})$

$92=\frac{x}{2}$

Value of x is

$x=92(2)$

x = 184

The value of x is 184°.

4 0

3 years ago

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran

mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

$X=48$ number of vehicles classified as sports utility.

$n=500$ random sample taken

$\hat p=\frac{48}{500}=0.096$ estimated proportion of vehicles classified as sports utility vehicles.

$p$ true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070$

$0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121$

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0

3 years ago

A company is allowed to interview candidates until two qualified candidates are found. But budget constraints dictate that no mo

Lapatulllka [165]

Answer:

Kindly check attached picture for sample space design

45 ways

Step-by-step explanation:

Number of qualified candidates to be chosen = 2

Number of candidates to be interviewed = 10

Combination formula :

nCr = n! / (n-r)! r!

10C2 = 10! ÷ (10 - 2)!2!

10C2 = 10*9 / 2 * 1

10C2 = 90/2

10C2 = 45 different samples

Our sample space will contain 45 different samples

4 0

3 years ago

Which equation could have been used to create this function table?

Ierofanga [76]

It would be c. y = x because if you plug in the numbers, it would be true

8 0

3 years ago

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