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kykrilka [37]
2 years ago
11

Write 9.55 as a mixed number

Mathematics
1 answer:
jeka57 [31]2 years ago
7 0

9.55 as a mixed number would be 9 11/20.

9.55 = 9 55/100 = 9 11/20

Hope this helps !

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Forty- two people attended s meeting about a zoning ordinance. Six more of the attendees voted in favor of the ordinance than th
kumpel [21]
Let the attendees in opposition be x. This means that the attendees in favour are x+6.
That means x+x+6=42, which is 2x+6=42, so 2x=36 and x=18. Therefore, there are 18 attendees who opposed it.
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Samantha sends her son, barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo
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45d+70=$880. $880-70=$810. 810/45=18
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Read 2 more answers
{x^2+6x-27/x^2-9x+18<br> how to solve step by step
Alika [10]

Answer:

Step-by-step explanation:

Step by Step Solution:

More Icon

STEP

1

:

5

Simplify ———————

x2 - 81

Trying to factor as a Difference of Squares:

1.1 Factoring: x2 - 81

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 81 is the square of 9

Check : x2 is the square of x1

Factorization is : (x + 9) • (x - 9)

Equation at the end of step

1

:

(((x2)-18x)+81) 5

———————————————•———————————

(((x2)-6x)-27) (x+9)•(x-9)

STEP

2

:

x2 - 18x + 81

Simplify —————————————

x2 - 6x - 27

Trying to factor by splitting the middle term

2.1 Factoring x2 - 18x + 81

The first term is, x2 its coefficient is 1 .

The middle term is, -18x its coefficient is -18 .

The last term, "the constant", is +81

Step-1 : Multiply the coefficient of the first term by the constant 1 • 81 = 81

Step-2 : Find two factors of 81 whose sum equals the coefficient of the middle term, which is -18 .

-81 + -1 = -82

-27 + -3 = -30

-9 + -9 = -18 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -9

x2 - 9x - 9x - 81

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-9)

Add up the last 2 terms, pulling out common factors :

9 • (x-9)

Step-5 : Add up the four terms of step 4 :

(x-9) • (x-9)

Which is the desired factorization

Trying to factor by splitting the middle term

2.2 Factoring x2-6x-27

The first term is, x2 its coefficient is 1 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is -27

Step-1 : Multiply the coefficient of the first term by the constant 1 • -27 = -27

Step-2 : Find two factors of -27 whose sum equals the coefficient of the middle term, which is -6 .

-27 + 1 = -26

-9 + 3 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 3

x2 - 9x + 3x - 27

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-9)

Add up the last 2 terms, pulling out common factors :

3 • (x-9)

Step-5 : Add up the four terms of step 4 :

(x+3) • (x-9)

Which is the desired factorization

Canceling Out :

2.3 Cancel out (x-9) which appears on both sides of the fraction line.

Equation at the end of step

2

:

(x - 9) 5

——————— • —————————————————

x + 3 (x + 9) • (x - 9)

STEP

3

:

Canceling Out

3.1 Cancel out (x-9) which appears on both sides of the fraction line.

Final result :

5

—————————————————

(x + 3) • (x + 9)

5 0
2 years ago
Manny makes dinner using 1 box of pasta and 1 jar of sauce. if pasta is sold in packages of 6 boxes and sauce is sold in package
natka813 [3]
<span>You need to find the least common multiple of 6 and 3. This the minimum whole number that contains the number of boxes in one package of pasta and the number of jars in one package of sauce. t he least common multiple of 6 and 3 is 6. This means that Manny can make 6 dinners, which will be made with 1 package of pasta (6 boxes ) and two packages of sauce (2 * 3 = 6 jars).</span>
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2 years ago
Charlie reads quickly. He reads 1\dfrac371 7 3 ​ 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 ​ st
OLEGan [10]
<h2>Answer:</h2>

The number of pages he will read in one minute is:

        2\dfrac{1}{7}\ \text{pages}

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads 1\dfrac{3}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

We know that:

1\dfrac{3}{7}=\dfrac{10}{7}

This means that:

Charlie reads \dfrac{10}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

This means that:

\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}

4 0
3 years ago
Read 2 more answers
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