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xeze [42]
3 years ago
11

Helpo me don’t bully meeeeeEEEE

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

1. x≥−1

2.x<4

3.x ≤ 1

4.x≥−2

5.x<−3

6.x≤7

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Mr. Brown had a orchard of apple trees, a fire took out thirty trees. The remaining trees produced 130 apples each for a total o
elena-14-01-66 [18.8K]

Answer: 90

Step-by-step explanation: 11,700 divided by 130 is 90 Therefore Mr. Brown started with 90 apple trees. Hope this helps :) sorry if I'm wrong

3 0
3 years ago
Read 2 more answers
Find r if 0=pi/6 rad sector 64m^2
kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is \theta=\dfrac{\pi}{6}.

To find:

The radius or the value of r.

Solution:

Area of a sector is:

A=\dfrac{1}{2}r^2\theta

Where, r is the radius of the circle and \theta is the central angle of the sector in radian.

Putting A=64,\theta=\dfrac{\pi}{6}, we get

64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}

64=\dfrac{\pi}{12}r^2

64\times \dfrac{12}{\pi}=r^2

\dfrac{768}{\pi}=r^2

Taking square root on both sides, we get

\sqrt{\dfrac{768}{\pi}}=r

16\sqrt{\dfrac{3}{\pi}}=r

Therefore, the value of r is 16\sqrt{\dfrac{3}{\pi}} m.

6 0
3 years ago
The measures of the angles of the triangle solve for x
maksim [4K]

Answer:

x = 8

Step-by-step explanation:

if the angle is equal to 36º that means (3x+12)º = 36º so simplify the equation and solve for x

3x+12 = 36

3x = 24

x = 8

4 0
3 years ago
Read 2 more answers
Find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -Si (Show all work to earn credit.)
antoniya [11.8K]

Answer:  The required polynomial of lowest degree is p(x)=x^3-2x^2+25x-50

Step-by-step explanation:  We are given to find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -5i.

We know that

if x = a is a zero of a real polynomial function p(x), then (x - a) is a factor of the polynomial p(x).

So, according to the given information, (x - 2) and ( x + 5i) are the factors of the given polynomial.

Also, we know that complex zeroes occur in conjugate pairs, so 5i will also be a zero of the given polynomial.

This implies that (x - 5i) is also a factor of the given polynomial.

Therefore, the polynomial of lowest degree (three) with real coefficients having zeroes of 2 and -5i is given by

p(x)=(x-2)(x+5i)(x-5i)\\\\\Rightarrow p(x)=(x-2)(x^2-25i^2)\\\\\Rightarrow p(x)=(x-2)(x^2+25)\\\\\Rightarrow p(x)=x^3-2x^2+25x-50

Thus, the required polynomial of lowest degree is p(x)=x^3-2x^2+25x-50

4 0
4 years ago
Which answer choise discreabe the ratio 6:4 selcet all that apply
stiv31 [10]

Answer:

3x:4x for some real number x

Step-by-step explanation:

Since answer choices weren't provided, I generalized my answer.

First, notice we can simplify 6:4 into 3:2 because we can write the ratio as a fraction and simplify (6 and 4 are both multiples of 2).

Since 3 and 2 are relatively prime and the ratio cannot simplify anymore, we can say that the ratio of 6:4 = 3:2 = 3x:2x for some real number x because we can see that 3x:2x = 3:2  by simplifying  (3x and 3 are both multiples of x).

As long as the answer choice you choose matches the format above, you should be correct! I hope this helps! :)

8 0
3 years ago
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