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ValentinkaMS [17]
2 years ago
10

Ratio in simplest form. 300, 30,3,

Mathematics
1 answer:
Irina18 [472]2 years ago
4 0

Answer:

100,10,1

dividing by 3 we get the above answers

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The median number of coloring contests won by 4 kids in a certain year is 5. The range of number of contests won by those kids t
Orlov [11]
True
bcause the median number is 5
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3 years ago
Yesterday, Sharon read 14 pages of a book. Today, she continued reading the book at the same speed. She read 10 pages in 35 minu
horrorfan [7]

Answer:

Sharon spent a total of 49 minutes yesterday reading the book

Step-by-step explanation:

Step 1: Calculate the rate at which she reads

The total number of pages she reads at any given time interval can be expressed as;

T=P×m

where;

T=Total number of pages she reads

P=the rate at which she reads in number of pages per minute

m=total number of minutes she takes reading a book

In our case;

T=10 pages

P=p

m=35 minutes

replacing;

10=p×35

p=10/35

p=(10/35)

The rate at which she reads=(10/35) pages per minute

Step 2: Calculate the time she spent reading the book yesterday

Yesterdays variables are as follows;

T=14 pages

p=(10/35) pages per minute

m=unknown

replacing;

14=(10/35)×m

m=14×(35/10)

m=49

Sharon spent a total of 49 minutes yesterday reading the book

8 0
4 years ago
How do write 2 3/4 as an improper fraction
kolezko [41]
11/4 is the mixed fraction of that
8 0
3 years ago
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At the market, 2.4 pounds of peas cost 1.68 dollars. How much does one pound of peas cost?
babunello [35]
.7

because you need to get the original unit price which is 0.7 then multiply that by 1 and get your answer
6 0
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Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
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